Javascript code to find target sum

Javascript code to find two numbers that sum up to the target sum from an array and return empty empty if not

1. First Method

function twoNumberSum(array, targetSum) {
    let result = []
        for (let i = 0; i < array.length; i++) {
          for (let j = i+1; j < array.length; j++) {
              if (array[i] + array[j] === targetSum) {
                  result.push(array[i])
                  result.push(array[j])
                  return result
              }
          }
      }
      return result
}

console.log(twoNumberSum([9,1,3,4,5], 6)) // [1,5]
console.log(twoNumberSum([1,2,3,4,5], 10)) // []

2. Second Method

function twoNumberSum(array, targetSum) {
	let sortedArray = array.sort((a,b) => a-b)
	let leftLimit = 0
	let rightLimit = sortedArray.length-1

	while (leftLimit < rightLimit) {
			const currentSum = sortedArray[leftLimit] + sortedArray[rightLimit]

			if (currentSum === targetSum) return [sortedArray[leftLimit], sortedArray[rightLimit]]
			else currentSum < targetSum ? leftLimit++ : rightLimit--        
	}

	return []
}

console.log(twoNumberSum([9,1,3,4,5], 6)) // [1,5]
console.log(twoNumberSum([1,2,3,4,5], 10)) // []

3. Third Method

function twoNumberSum(array, targetSum) {
	let result = []

	for (let i = 0; i < array.length; i++) {
        let desiredNumber = targetSum - array[i]
        if (array.indexOf(desiredNumber) !== -1 && array.indexOf(desiredNumber) !== i) {
            result.push(array[i])
            result.push(array[array.indexOf(desiredNumber)])
            break
        }
	}

    return result
}

console.log(twoNumberSum([9,1,3,4,5], 6)) // [1,5]
console.log(twoNumberSum([1,2,3,4,5], 10)) // []